KBSEKT G 1 ;BEHEER SEKTOREN ;KBSEKT; [ 08/05/2002  10:33 AM ]
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1 S K=$P($T(+1),";",2)_QN_" ",FP=203+$L(K) W @F61,@F11,@F1,@F,@F5 S FP=202 W @F,@F4,K,@F5
2 L  S ISEK="",FP=301 W @F,@F1
3 S ISEK=$N(@("^"_Q_"SEKT(ISEK)")),VVE=1 G 5:ISEK=-1 S FP=FP+100 W @F,$C(13),?2,ISEK,": ",^(ISEK)
4 G 3:FP<1600 S VVE=$N(@("^"_Q_"SEKT(ISEK)"))=-1
5 S R="SEKT\21\4\KODE SEKTOR \C1\3\\$L(K)" D S0 G YZ:K="-"
50 I K="D" D 10^KDSEKT G 2:K="-",1
6 I K="" S FP=301 W @F,@F1 G 2:VVE,3
7 S SEKT=SEKT_" " I $D(@("^"_Q_"SEKT(SEKT)")) W " = ",@("^"_Q_"SEKT(SEKT)")
10 L @("^"_Q_"SEKT(SEKT)"):2 E  S FP=2403+F60 W @F,@F4,"KODE SEKTOR ",SEKT,"IS IN GEBRUIK ! [] = OK ",@F5,@F0 R K G 5
15 S R="K\22\4\OMSCHRIJVING\C2\25\\K=""V""&$D(@(""^""_Q_""SEKT(SEKT)""))!$L(K)" D S0 G 2:K="-"!(K=","),21:K'="V"
17 S FP=2238+F60 W @F,@F1 S R="K\23\4\V[] = verwijderen definitief   -[] = hernemen\\1\\""-V""[K&$L(K)\" D S0 G 15:K="-"
19 K @("^"_Q_"SEKT(SEKT)") S FP=2403+F60 W @F,@F2,@F4,"KODE SEKTOR ",SEKT,"IS VERWIJDERD ! [] = OK ",@F5,@F0 R K G 2
21 S @("^"_Q_"SEKT(SEKT)")=K G 2
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YZ Q
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S0 S S7="K'[D&(K'?.E1C.E)" S:$P(R,D,8)'="" S7=S7_","_$P(R,D,8) S:$P(R,D,7)'="" S7=S7_","_$P($T(@$P(R,D,7))," ",2,99)
S0A S S2=$P(R,D,2),S3=$P(R,D,3),S4=$P(R,D,4),S5=$P(R,D,5),S6=$P(R,D,6)
S0B S S0=$L(S4)+S3+3 S FP=S2*100+S3+F60 W @F,@F1 W @F2,S4," : " I S5'="" W:S5["""" !,?2,@S5 D:S5'["""" @S5
S0C S FP=S2*100+S0+F60 W @F,@F2 W $E("......................................................................",1,S6),@F,@F0
S0D R K W @F2 I $L(K)'>S6,@S7 S @$P(R,D,1)=K
S0E E  G S0C
S0F S FP=$P(R,D,9)*100+($P(R,D,10)*1) I FP W @F,$E("                                        ",1,S6),@F,K
S0Z K R,S0,S2,S3,S4,S5,S6,S7 Q  ;V3 23.08.84
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C1 W !?3 W:'VVE "[] = vervolg   " W "D[] = drukken   -[] = einde ingave" Q
C2 W !?3 W:$D(@("^"_Q_"SEKT(SEKT)")) "V[] = verwijderen kode sektor" Q
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